Cryptography is all about defending against attacks by intelligent adversaries. What purpose does the attack tag serve that is not served by the mere use of Crypto.SE as a medium in the first place? Should we delete it?
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asked Sep 28, 2019 at 18:07
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$\begingroup$ ..... bump ..... $\endgroup$– Maarten Bodewes ModCommented Oct 22, 2019 at 18:59
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$\begingroup$ The votes are tied but so far nobody has written a reason why the attack tag is helpful for categorization. $\endgroup$– Squeamish OssifrageCommented Oct 23, 2019 at 2:49
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2 Answers
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We should delete the attack tag because it is implied by the mere use of Crypto.SE as a medium.
(There are plenty of tags for more specific models of attacks like chosen-ciphertext-attack; the attack tag does not serve this purpose.)
answered Sep 28, 2019 at 18:09
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We should keep the attack tag because…
It seems hard to anticipate all the types of attack, and consequently all the categories that would cover this concept. [Can you please expand on how this is helpful for categorization? For example, which questions doesn't it apply to?]
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$\begingroup$ Fun stuff: because an attacker provides a good badge name! $\endgroup$– kelalakaCommented Sep 28, 2019 at 19:23
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$\begingroup$ (Continue: Comment restriction reached max) These 5 question has nothing but attack tag. If we close we have to find a proper tag for them. $\endgroup$– kelalakaCommented Sep 28, 2019 at 19:28
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$\begingroup$ @kelalaka I suggested closing the two that are unclear and tagged the two remaining ones with more appropriate tags. $\endgroup$ Commented Sep 28, 2019 at 19:56
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... attack vectors...question may needattack vectors$\endgroup$– kelalakaCommented Sep 28, 2019 at 20:01 -
$\begingroup$ @kelalaka What purpose would that serve? The question is an algorithm design question: Is $(x_1, x_2, \dots, x_{k-1}, \hat x, x_{k+1}, \dots, x_n)$ a secure cipher for message $\hat x$, random $x_i$, and secret key $k$? How would a generic
attackorattack-vectorstag help to organize it? $\endgroup$ Commented Sep 28, 2019 at 20:03 -
1$\begingroup$ Yes, it is not related to this question. Information security has an attack-vector tag. info:
Attack vectors are methods and channels used by attackers during a hacking attempt.Therefore, we don't need. $\endgroup$– kelalakaCommented Sep 28, 2019 at 20:07