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e-sushi Mod
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Tweeted twitter.com/StackCrypto/status/907279465117622273
Clarified to handle fkraiem's comment ["Is clearly about C coding." How do you know? C is mentioned nowhere in the question.](https://crypto.meta.stackexchange.com/questions/951/how-can-we-modify-our-close-reason-and-help-center-texts-to-allow-some-coding?noredirect=1#comment2735_951)
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e-sushi Mod
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Is clearly about Ccryptographic coding (I'm guessing C, based on the Q's code snippet and the answers which agree by talking about C). CompilerAlso, the compiler-related talk in all answers underline thisthe fact the question is about cryptographic coding.

Is clearly about C coding. Compiler-related talk in all answers underline this fact.

Is clearly about cryptographic coding (I'm guessing C, based on the Q's code snippet and the answers which agree by talking about C). Also, the compiler-related talk in all answers underline the fact the question is about cryptographic coding.

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e-sushi Mod
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As for the linked Q itself, I've dropped a 4th vote to reopen the Q&A which has an accepted answer. Yet, that does not mean the problems and reasons described in this META Q&A are voided. Reopening the question actually enforces the problem that users might start using this and other questions as evidence that they can ask similar, but off-topic questions. That's why we definitely need to clarify things so we stay clear of turning into a StackOverflow duplicate.

As for the linked Q itself, I've dropped a 4th vote to reopen the Q&A which has an accepted answer. Yet, that does not mean the problems and reasons described in this META Q&A are voided.

As for the linked Q itself, I've dropped a 4th vote to reopen the Q&A which has an accepted answer. Yet, that does not mean the problems and reasons described in this META Q&A are voided. Reopening the question actually enforces the problem that users might start using this and other questions as evidence that they can ask similar, but off-topic questions. That's why we definitely need to clarify things so we stay clear of turning into a StackOverflow duplicate.

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